Charging a Capacitor Through a Resistor
Lesson notes
Overview
The voltage across a capacitor rises toward the supply voltage exponentially. This topic is rated advanced and is number 202 of 227 in Physics. Deeper models, formal results and harder reasoning.
What you are seeing
The panel above shows a graph of the function. Each slider changes one parameter, so you can see exactly how the curve bends, shifts or stretches. The animation is drawn live from the model, so everything you see responds to the sliders. Press Space to pause, use Restart to replay from the start, and change the speed to slow down quick events.
In depth
When a capacitor is charged from a supply V₀ through a resistor, the current starts large and falls as the capacitor voltage rises: V = V₀(1 − e^(−t/RC)). After one time constant RC it reaches 63%, after two 86%, and after five 99%. The same time constant governs the discharge. The rate is determined by how fast charge can flow through R, and the capacitor’s capacity to hold it. It sets the timing in oscillators and delay circuits.
Reading the relationship
The expression "V = V₀(1 − e^(−t/RC))" is a compact summary of the idea. It uses the symbols V, V₀, e, t, R, C; name what each one stands for before you start. Notice that it contains a ratio, so increasing the denominator makes the result smaller, and an exponential, which changes by the same factor for every equal step. Then use the sliders to see how changing one quantity changes the others.
A guided exploration
1. Set every slider to its middle value and note the shape of the curve. 2. Move one slider at a time and describe whether the curve shifts, stretches or turns. 3. Find the value where the behaviour changes sharply, then connect it to the formula.
Try this
Try to explain why the pattern holds, not just what it is. Look for limiting cases and what happens at the edges.
Common pitfalls
Check units and directions first. Many mistakes come from mixing up a scalar with a vector, or from using a formula outside the conditions where it holds.
How it connects
It builds on “Hall Voltage”, the topic before it in Physics. Once you are comfortable, continue with “Maxwell’s Equations in Words”.
Why it matters
Physics explains how the world moves, heats, shines and interacts, and the same principles power technology around you.
Where you might use it
- Revising “Charging a Capacitor Through a Resistor” before a class, exam or certification
- Designing vehicles, bridges and devices where motion, forces or waves must be predicted
- Understanding how sensors, lasers and communication links actually work
- Explaining everyday phenomena such as sound, light, heat and orbits
Frequently asked questions
What is Charging a Capacitor Through a Resistor?
The voltage across a capacitor rises toward the supply voltage exponentially. It is an advanced topic in Physics.
How do I use the Charging a Capacitor Through a Resistor simulation?
The panel at the top shows a graph of the function. Each slider changes one parameter, so you can see exactly how the curve bends, shifts or stretches. Move the sliders one at a time, then press Space to pause the animation and look closer.
What does the formula mean?
The expression V = V₀(1 − e^(−t/RC)) packs the idea into symbols. Name each symbol first, then change one quantity with the sliders and see which others respond.
Who is this topic for?
Deeper models, formal results and harder reasoning. If the quiz feels hard, reread the lesson notes and try the previous topic first.
What should I learn before this?
Start with “Hall Voltage”, the previous topic in Physics. Each topic in a subject builds on the ones before it.
How do I track my progress?
Press “Mark as learned” on this page. Progress is stored only in this browser and is never sent anywhere. The Browse page can show topics you have learned or still need to learn.